Asked by beth

If a person radiates about 74 W of power at room temperature, how long does it take for a person to radiate away the energy acquired by consuming a 235 Calorie doughnut?
Answered by DrBob222
http://scienceshareware.com/bicycle-generator-faq.htm#calories
Answered by Mark
A Calorie with a capital C is 1 kilocalorie. 1c=4.184 J, so 1kc=4,184 J. 235 C X 4,184 J = 983,240 J. 1 W is 1 J/second. Divide 983,240 J by 74 J/s, to get 13287.02703 seconds. Divide that by 3600 seconds/hour to convert to hours.

Answer in short: 13287.02703 s = 3.690840841 hours.
Answered by lizia
thank you! that was very helpful!
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