Asked by Anonymous

A note played by a musical instrument has a frequency of 130.8 Hz. What would be the length of the pipe if an organ pipe had this frequency as the fundamental and if the speed of the sound in the pipe is 350 m/s?

f = v/2L
130.8(2L) = 350
2L = 2.68
L is about 1.34 m.
Answered by bobpursley
assume organ pipe is open at one end.

2L=one half wavelength=speed/2f
2L=350/130.8
L= 1.34m
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