Asked by Anonymous
                A note played by a musical instrument has a frequency of 130.8 Hz. What would be the length of the pipe if an organ pipe had this frequency as the fundamental and if the speed of the sound in the pipe is 350 m/s?
f = v/2L
130.8(2L) = 350
2L = 2.68
L is about 1.34 m.
            
        f = v/2L
130.8(2L) = 350
2L = 2.68
L is about 1.34 m.
Answers
                    Answered by
            bobpursley
            
    assume organ pipe is open at one end.
2L=one half wavelength=speed/2f
2L=350/130.8
L= 1.34m
    
2L=one half wavelength=speed/2f
2L=350/130.8
L= 1.34m
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