Asked by chanel

A stock solution of HNO3 is prepared and found to contain 11.1 M of HNO3. If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L, the concentration of the diluted solution is ________ M.

Answers

Answered by DrBob222
11.1 M x (25.0 mL/500 mL) = ?

OR use the dilution formula.
mL1 x M1 = mL2 x M2
25.0 x 11.1 = 500 mL x M2.
Solve for M2.
Answered by CoJo
0.555
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