Asked by physics
A stone of 2kg is projecter vertically as a velocity of 5m/s at an angle of 60.calculate,the time taking?the maximum hight?the range
Answers
Answered by
Damon
Nothing to do with the mass.
I assume you mean 60 degrees from horizontal in which case the initial vertical velocity component is 5 sin 60 = 4.33
v = 4.33 - 9.81 t
at top v = 0 so
t = 4.33/9.81 = .441 seconds upward bound
h = 4.33 t - 4.9 t^2
for range use 2 t (upward and downward)
= range = .882* 5 cos 60 = .441*5
= 2.2 meters
I assume you mean 60 degrees from horizontal in which case the initial vertical velocity component is 5 sin 60 = 4.33
v = 4.33 - 9.81 t
at top v = 0 so
t = 4.33/9.81 = .441 seconds upward bound
h = 4.33 t - 4.9 t^2
for range use 2 t (upward and downward)
= range = .882* 5 cos 60 = .441*5
= 2.2 meters
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