Asked by Memos
A pool ball leaves a 0.6 m high table with an initial horizontal velocity of 2.4 m.s.calculate horizontal and vertical velocity and time taken for the pool ball to fall to the ground
Answers
Answered by
Damon
two problems connected only by falling time
vertical problem:
Vi = initial y velocity = 0
v = Vi - g t
h = Hi + Vi t - .5 g t^2
so at ground
0 = 0.6 + 0 - 4.9 t^2
t^2 = 0.6/4.9
t = 0.35 s to fall
v at ground = 9.81* 0.35
horizontal velocity = 2.4 until it hits
range = 2.4 * .35
vertical problem:
Vi = initial y velocity = 0
v = Vi - g t
h = Hi + Vi t - .5 g t^2
so at ground
0 = 0.6 + 0 - 4.9 t^2
t^2 = 0.6/4.9
t = 0.35 s to fall
v at ground = 9.81* 0.35
horizontal velocity = 2.4 until it hits
range = 2.4 * .35
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