Asked by Memos

A pool ball leaves a 0.6 m high table with an initial horizontal velocity of 2.4 m.s.calculate horizontal and vertical velocity and time taken for the pool ball to fall to the ground

Answers

Answered by Damon
two problems connected only by falling time

vertical problem:
Vi = initial y velocity = 0
v = Vi - g t
h = Hi + Vi t - .5 g t^2
so at ground
0 = 0.6 + 0 - 4.9 t^2
t^2 = 0.6/4.9
t = 0.35 s to fall

v at ground = 9.81* 0.35

horizontal velocity = 2.4 until it hits

range = 2.4 * .35


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