Question

A stone, 2kg is projected vertically at a velocity of 5m/s at an Angle of 60°
Calculate
I.Time taken to attain maximum height
II.maximum height reached
III.The range
Vo = 5m/s[60o].
Xo = 5*cos60 = 2.5 m/s.
Yo = 5*sin60 = 4.33 m/s.

1. Y = Yo + g*t.
0 = 4.33 - 9.8t, t = ?.

2. Y^2 = Yo^2 + 2g*h.
0 = 4.33^2 - 19.6h, h = ?.

3. Range = Vo^2*sin(2A)/g.
Range = 5^2*sin(120)/9.8 =

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