Asked by Busola
Calculate the final centigrade temperature required to change 20 litres of gas at 120°C and 1 atmosphere to 25 litres at 2 atmosphere.
Answers
Answered by
Steve
PV=kT, so PV/T is constant
You want T such that
2*25/(T+273) = 1*20/(120+273)
You want T such that
2*25/(T+273) = 1*20/(120+273)
Answered by
jeremiah
the answer does no correspond
ond with the one on the textbook
ond with the one on the textbook
Answered by
Anonymous
What's the answer to the question?
Answered by
Cynthia
Busola
Pls what's the answer?
Pls what's the answer?
Answered by
Cynthia
Busola
The answer in the text book is 23 degree celcius and I don't seem to be getting it with ur formula.
The answer in the text book is 23 degree celcius and I don't seem to be getting it with ur formula.
Answered by
azeezat
Pls work out the question
Answered by
Praise
I don't get it
Answered by
Bob
Calculate the final centigrade temperature required to change 20 litres of gas at 120°C and 1 atmosphere to 25 litres at 2 atmospheres.
Pressure × Volume / Temperature = Number of molecules
PV / T = N
Convert 120°C to 393.15°K
Original state:
1 atmosphere × 20 Liters / 393.15°K = N moles
Final state:
2 atmosphere × 25 Liters / T°K = N moles (solve for T)
Since N remains constant, we can combine the two statements:
1 × 20 / 393.15 = 2 × 25 / T
Solution:
20 / 393.15 = 50 / T
0.05087116877 = 50 / T
T × 0.05087116877 = 50
T = 50 / 0.05087116877
T = 982.875°K
T = 709.725°C
Pressure × Volume / Temperature = Number of molecules
PV / T = N
Convert 120°C to 393.15°K
Original state:
1 atmosphere × 20 Liters / 393.15°K = N moles
Final state:
2 atmosphere × 25 Liters / T°K = N moles (solve for T)
Since N remains constant, we can combine the two statements:
1 × 20 / 393.15 = 2 × 25 / T
Solution:
20 / 393.15 = 50 / T
0.05087116877 = 50 / T
T × 0.05087116877 = 50
T = 50 / 0.05087116877
T = 982.875°K
T = 709.725°C