Asked by Busola

Calculate the final centigrade temperature required to change 20 litres of gas at 120°C and 1 atmosphere to 25 litres at 2 atmosphere.

Answers

Answered by Steve
PV=kT, so PV/T is constant
You want T such that

2*25/(T+273) = 1*20/(120+273)
Answered by jeremiah
the answer does no correspond
ond with the one on the textbook
Answered by Anonymous
What's the answer to the question?
Answered by Cynthia
Busola
Pls what's the answer?
Answered by Cynthia
Busola
The answer in the text book is 23 degree celcius and I don't seem to be getting it with ur formula.
Answered by azeezat
Pls work out the question
Answered by Praise
I don't get it
Answered by Bob
Calculate the final centigrade temperature required to change 20 litres of gas at 120°C and 1 atmosphere to 25 litres at 2 atmospheres.

Pressure × Volume / Temperature = Number of molecules
PV / T = N
Convert 120°C to 393.15°K

Original state:
1 atmosphere × 20 Liters / 393.15°K = N moles

Final state:
2 atmosphere × 25 Liters / T°K = N moles (solve for T)

Since N remains constant, we can combine the two statements:
1 × 20 / 393.15 = 2 × 25 / T

Solution:
20 / 393.15 = 50 / T
0.05087116877 = 50 / T
T × 0.05087116877 = 50
T = 50 / 0.05087116877
T = 982.875°K
T = 709.725°C

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