Asked by Eric

I have answered the question but not sure how to check for extraneous solution.

x/(5x+4)=3

The answer is -6/7
Answered by Eric
X=-6/7

This was answer to the problem
Answered by collins
x/(5x+4)=3

x=3(5x+4)
x=15x+12
x-15x=12
-14x=12
-7x=6
x=-6/7

there you go find algebra difficult?
Answered by Eric
I have that but it tells me to check for extraneous solutions and that is where I am lost for this problem
Answered by collins
forget about that grammer just smile with your solution

and learn to use your dictionary although i am not a fan of english
But
In mathematics, an extraneous solution (or spurious solution) is a solution, such as that to an equation, that emerges from the process of solving the problem but is not a valid solution to the original problem.
Answered by Reiny
Extraneous roots mostly occur after squaring an equation.
Since you verified your solution by subbing it back into the <b>original</b> equation, there are no extraneous roots

LS = x/(5x+4)
= (-6/7) / (5(-6/7) + 4)
= (-6/7) / (-2/7)
= (-6/7)(-7/2) = 42/14 = 3
= RS
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