Asked by Angel
1.38 mol HCl and 2.9 mol NaOH react accord-
ing to the equation
HCl + NaOH −→ NaCl + H2O .
If the limiting reactant is HCl, determine
the amount of excess reactant that remains.
Answer in units of mol.
ing to the equation
HCl + NaOH −→ NaCl + H2O .
If the limiting reactant is HCl, determine
the amount of excess reactant that remains.
Answer in units of mol.
Answers
Answered by
DrBob222
mol HCl initially = 1.38
mol NaOH initially = 2.90
mol NaOH after reacting = 2.90 - 1.38 = ? mols.
mol NaOH initially = 2.90
mol NaOH after reacting = 2.90 - 1.38 = ? mols.
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