Asked by Killian

A man pulls a box with a force of 70N along the positive y-axis,while a boy pulls it with a force of 50N,making an angle of 80 degrees counter clock-wise with the positive y-axis.
(i)In what direction should a second boy apply a force of 60N so that the box move along the positive y-axis?Hint;Two values are Posible.
(ii). Find the magnitude and direction of the force that a second man should apply to that the box does not move at all?
PLS HELP ME
Answered by Henry
F1 = 70N[90o].
F2 = 50N[170o], CCW from +x-axis.
F3 = 60N[Xo].

F3*Cos X = -F2*Cos170.
60*Cos X = -50*Cos170,
Cos X = 0.82067, X = 34.8o.
Answered by Henry
F1 = 70N[90o].
F2 = 50N[170o], CCW from +x-axis.
F3 = 60N[Xo].

1. The hor. component of F2 and F3 must be equal and opposite:
F3*Cos X = -F2*Cos170.
60*Cos X = -50*Cos170,
Cos X = 0.82067, X = 34.8o.

2.
Answered by Henry
2. F4 =-(F1*sin90+F2*sin170+F3*sin34.8)F4 = -(70 + 8.68 + 34.2) = -113 N. = 113 N. Downward.

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