Asked by juan
A boy pulls a sled with a force of 10.0 lb for 100.0 ft. The rope attached to the sled is at an angle 30.0 ̊ above the horizontal. (a) How much work is done? (b) If the boy moves the sled 100.0 ft in 45 s, find his power output in horsepower.
Answers
Answered by
Anonymous
work = force * displacement in direction of force
= 10.0 * 100 cos 30 = 866 ft lbs
power = 866/45 = 19.2ft lbs/s * ( 0.0018 hp / 1 ft lb/s) = 0.0346 hp
= 10.0 * 100 cos 30 = 866 ft lbs
power = 866/45 = 19.2ft lbs/s * ( 0.0018 hp / 1 ft lb/s) = 0.0346 hp
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