Question

Solve the equation

3^5sqrt(x+2)^3+3=27

My answer is 30

Answer 1

Did you sub in the value of 30 to see if you are correct?
Following the order of operations, I get:
left side = 243(√32)^3 + 3
= appr 43990.7 , certainly ≠ 27


3^5sqrt(x+2)^3+3=27
3^5sqrt(x+2)^3 = 24
243√(x+2)^3 = 24
√(x+2)^3 = 8/81
(x+2)^(3/2) = 8/81
x+2 = (8/81)^(2/3) = appr .2137
x = appr -1.7863

Answer 2

thank you

Answer 3

I got 36.9, don't quote me but I'll post a brainly and ask a tutor

Answer 4

3 ^5√(x+2)^3 +3=27
isolate the radical
3 ^5√(x+2)^3 =24
divide by 3
^5√(x+2)^3 =8
set the radical to the power of 5 to cancel out the sqrt and also set 8 to the power of 5
(x+2)^3 = 32768
cube root to cancel out the exponent of three
x+2=32
-2
x=30

i hope that made sense, idk if it’s right