Asked by Latoya
Solve
s2 + 5s + 7 = 0
s2 + 5s + 7 = 0
Answers
Answered by
drwls
Please use a ^ symbol before exponents.
s^2 + 5s + 7 = 0
In that equation, the coefficients of the three terms are
a=1, b=5, and c = 7
Use this formula for the answer:
s = [-b +/- sqrt (b^2-4ac)]/2a
Just plug in the numbers. You will get complex roots in this case, since b^2-4ac = -3 <0.
s^2 + 5s + 7 = 0
In that equation, the coefficients of the three terms are
a=1, b=5, and c = 7
Use this formula for the answer:
s = [-b +/- sqrt (b^2-4ac)]/2a
Just plug in the numbers. You will get complex roots in this case, since b^2-4ac = -3 <0.
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