Asked by Anonymous

Find the exact value of sinA where a=9 and b=10 and angle C is a right angle.

a. sin A= 9/sqrt 181, cos A= sqrt 181/10

b. sin A= sqrt 181/9, cos A= 10/sqrt 181

c. sin A= 9/sqrt 181, cos A= 10/sqrt 181

d. sin A=sqrt181/10, cos A= 9/sqrt 181

Answers

Answered by bobpursley
sin A= 9/sqrt181, cosA=10/sqrt181
Did you sketch the right triangle?
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