Asked by Anonymous
Find the exact value of sinA where a=9 and b=10 and angle C is a right angle.
a. sin A= 9/sqrt 181, cos A= sqrt 181/10
b. sin A= sqrt 181/9, cos A= 10/sqrt 181
c. sin A= 9/sqrt 181, cos A= 10/sqrt 181
d. sin A=sqrt181/10, cos A= 9/sqrt 181
a. sin A= 9/sqrt 181, cos A= sqrt 181/10
b. sin A= sqrt 181/9, cos A= 10/sqrt 181
c. sin A= 9/sqrt 181, cos A= 10/sqrt 181
d. sin A=sqrt181/10, cos A= 9/sqrt 181
Answers
Answered by
bobpursley
sin A= 9/sqrt181, cosA=10/sqrt181
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