Question
2. Suppose a chemistry student made 2000. mL of 6.00 M HCl. He accidently spilled half of this solution on the floor. What is the Molarity of HCL left in the beaker? Explain the answer...
- for this problem, would I use the eq'N, M1V1=M2V2.
3. What is the molarity of a sol'n that contains 28.5 g of KOH in 2.00 L of sol'n?
5. If 500. ml of 2.0 M H2SO4 is diluted with water to a volume of 1.00 L, what is the molarity of the new solution.
- for this problem, would I use the eq'N, M1V1=M2V2.
3. What is the molarity of a sol'n that contains 28.5 g of KOH in 2.00 L of sol'n?
5. If 500. ml of 2.0 M H2SO4 is diluted with water to a volume of 1.00 L, what is the molarity of the new solution.
Answers
bobpursley
2. The lost solution does not change the molarity of what is left in the beaker.
3. M=(28.5/40)/2
4. you are diluting it by a factor of 2. New molarity=1M
3. M=(28.5/40)/2
4. you are diluting it by a factor of 2. New molarity=1M
Lina
2. I still don't get this or is it the same equation.
3. Answer: 0.254 M KOH
5. Am I still using the equation?
3. Answer: 0.254 M KOH
5. Am I still using the equation?
Lina
Is #5's answer: 1.0 M H2SO4?
what about #2?
what about #2?