Question
A chemistry student weighs out 0.172 grams of acrylic acid (HCH2CHCO2) into a volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1800 moles/liter NaOH solution.
Calculate the volume of NaOH solution the student will need to add to reach the equivalence point.
Calculate the volume of NaOH solution the student will need to add to reach the equivalence point.
Answers
moles acrylic acid = grams/molar mass
moles acrylic acid = moles NaOH.
M NaOH = moles NaOH/L NaOH.
You know M NaOH and moles NaOH, solve for L NaOH and convert to mL.
moles acrylic acid = moles NaOH.
M NaOH = moles NaOH/L NaOH.
You know M NaOH and moles NaOH, solve for L NaOH and convert to mL.