moles acrylic acid = grams/molar mass
moles acrylic acid = moles NaOH.
M NaOH = moles NaOH/L NaOH.
You know M NaOH and moles NaOH, solve for L NaOH and convert to mL.
Calculate the volume of NaOH solution the student will need to add to reach the equivalence point.
moles acrylic acid = moles NaOH.
M NaOH = moles NaOH/L NaOH.
You know M NaOH and moles NaOH, solve for L NaOH and convert to mL.
1. Calculate the molar mass of HCH2CHCO2:
H = 1.01 g/mol x 3 = 3.03 g/mol
C = 12.01 g/mol x 4 = 48.04 g/mol
O = 16.00 g/mol x 2 = 32.00 g/mol
Molar mass of HCH2CHCO2 = 3.03 g/mol + 48.04 g/mol + 32.00 g/mol = 83.07 g/mol
2. Convert the mass of acrylic acid to moles:
moles = mass / molar mass
moles = 0.172 g / 83.07 g/mol ≈ 0.00207 mol
3. The balanced chemical equation for the reaction between acrylic acid (HCH2CHCO2) and NaOH is:
HCH2CHCO2 + NaOH → CH3CHOHCO2Na + H2O
From the equation, we can see that 1 mole of acrylic acid reacts with 1 mole of NaOH.
4. Calculate the volume of NaOH solution needed:
moles = volume (L) × concentration (mol/L)
Given concentration = 0.1800 mol/L
volume (L) = moles / concentration
volume (L) = 0.00207 mol / 0.1800 mol/L ≈ 0.0115 L
Therefore, the student will need to add approximately 0.0115 liters (or 11.5 milliliters) of NaOH solution to reach the equivalence point.