Asked by Abi
A fighter accelerates from rest at 120,000 m/s^2 for a time of 4 seconds. How far did the jet fighter travel?
Answers
Answered by
Reiny
a = 120000 m/s^2
v = 120000t + c
when t=0, v = 0 , so c = 0
s = 60000t^2 + k , where s is the distance, k a constant
when t=0, the plane hasn't gone anywhere
so 0 = 0 + k, k = 0
s = 60000(t^2)
when t = 4, s = 60000(4) = ...
v = 120000t + c
when t=0, v = 0 , so c = 0
s = 60000t^2 + k , where s is the distance, k a constant
when t=0, the plane hasn't gone anywhere
so 0 = 0 + k, k = 0
s = 60000(t^2)
when t = 4, s = 60000(4) = ...
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