Question

Suppose one person decides to carry out a random act of kindness for three people on Monday. On Tuesday, that same person is kind to three more people, and the three he/she helped on Monday each help three more individuals. If the same circumstances were to occur on Wednesday, how many random acts of kindness would have been distributed?

I think it's 15. Is that right?

Answer 1

1 to 3

initial person does 3 and the other 3 each help 3

so that should be 12

wed.

the initial person does 3
and the other 9 each do 3

27 +3 = 30

Answer 2

63

Answer 3

30
1×3 = 3
1×3 = 3
3×3 = 9
= 15 but they do it again on Wednesday so 15×2= 30