Ask a New Question

Question

An automobile moving northward with a velocity of 270m/s is brought to rest in 45 seconds .
find the average acceleration durong this time interval.
express the answer in ft/sec^2
8 years ago

Answers

bobpursley
ft/sec^2? good lord.

270m/s=270m/s*3.28ft/m

vf=vi+at
a= (vf-vi)/t and vf=0
solve for a
8 years ago

Related Questions

an automobile moving at a constant velocity of 50 ft/sec passes a gasoline station. 3 sec later, an... A 989 kg automobile is moving at 15.6 m/s at a height of 5.0 m above the bottom of a hill when it ru... An automobile moving at a constant velocity of 15m/s passes a gasoline station. Two seconds later, a... A 1000kg automobile is moving along a straight highway at 10m/s. another car with mass 2000kg and mo... an automobile moving at constant velocity of 15m/sec passes a gasoline station. two seconds later an... An automobile is moving in an easterly direction at a velocity of 100km/hr. He sees an emergency... An automobile moving at a constant velocity of 15 m/s passes a gasoline station. Two seconds later,... A car travels in a northward direction for a total distance of 512 km. The car completes this trip i... Consider an automobile moving at v mph that skids d feet after its brakes lock. Calculate how far it...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use