Asked by caisip
An automobile moving at a constant velocity of 15 m/s passes a gasoline station. Two seconds later, another automobile leaves the station and accelerates at a constant rate of 2 m/s^2 in the same direction as the 1st automobile.
How soon does the 2nd automobile overtake the first?
How soon does the 2nd automobile overtake the first?
Answers
Answered by
Henry
d1 = 15m/s * 2s. = 30 m head start.
d2 = 0.5a*t^2 = 30 + 15t
1*t^2 = 30 + 15t
t^2 - 15t = 30
t^2 - 15t - 30 = 0
Use Quadratic Formula and get:
t = 16.79 s.
d2 = 0.5a*t^2 = 30 + 15t
1*t^2 = 30 + 15t
t^2 - 15t = 30
t^2 - 15t - 30 = 0
Use Quadratic Formula and get:
t = 16.79 s.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.