Asked by NR
Solve:
Log5(x-2) + log8(x-4)=
log6(x-1)
Log5(x-2) + log8(x-4)=
log6(x-1)
Answers
Answered by
Steve
If those are logs to the same base, then
5(x-2)*8(x-4) = 6(x-1)
x = (123+√2089)/40
If those are logs to different bases (5,8,6), it takes some more work. Changing all to natural logs, we have
Log5(x-2) + log8(x-4)=
log6(x-1)
ln(x-2)/ln5 + ln(x-4)/ln8 = ln(x-1)/ln6
ln8*ln6*ln(x-2) + ln5*ln6*ln(x-4) = ln5*ln8*ln(x-1)
x ≈ 5.1797
Other than a graphical or numerical method, I don't see how to arrive at a solution.
5(x-2)*8(x-4) = 6(x-1)
x = (123+√2089)/40
If those are logs to different bases (5,8,6), it takes some more work. Changing all to natural logs, we have
Log5(x-2) + log8(x-4)=
log6(x-1)
ln(x-2)/ln5 + ln(x-4)/ln8 = ln(x-1)/ln6
ln8*ln6*ln(x-2) + ln5*ln6*ln(x-4) = ln5*ln8*ln(x-1)
x ≈ 5.1797
Other than a graphical or numerical method, I don't see how to arrive at a solution.
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