Asked by Miguel Plaza
Consider the following reaction,
4 PH3(g) + 8 O2(g) → P4O10(s) + 6 H2O(g)
If a container were to have 32 molecules of PH3 and 32 molecules of O2 initially, how many total molecules (reactants plus products) would be present in the container after this reaction goes to completion? (Use only whole numbers to solve.)
4 PH3(g) + 8 O2(g) → P4O10(s) + 6 H2O(g)
If a container were to have 32 molecules of PH3 and 32 molecules of O2 initially, how many total molecules (reactants plus products) would be present in the container after this reaction goes to completion? (Use only whole numbers to solve.)