Question

Consider the following reaction:
H2(g) + I2(s) ---> 2HI(g)
TriangleH = 51.9 kj (enthalpy)

Calculate the standard enthalpies of reaction for the following reaction:

6HI(g) ---> 3H2(g) + 3I2(s)


Thanks!

Answer 1

You want the reverse of 3x the rxn.
That will be -51.9*3 kJ