Asked by Jaena MacCharlie lol
The 1205 kg physics dragster is traveing ay 35km(easy) when it hits the gas and accelerates at 12.5 m/s^2 for 3.25s. What is change in momentum during this time?
Answers
Answered by
bobpursley
is the initial speed 35km/hr? change that to m/s
momentumchange=mass*(vf-vi)
vf=vi+at=12.5*3.25m/s+vi
vf-vi=12.5*3.25 m/s
momentumchange=mass*(vf-vi)
vf=vi+at=12.5*3.25m/s+vi
vf-vi=12.5*3.25 m/s
Answered by
jAENA MACHARLIE LOL
BOB what i fail to understand is isnt Vf-vi=(12.5*3.25)-(9.722).
Answered by
Damon
No
The CHANGE in speed is acceleration times time
12.5 * 3.25
That is all you need
The initial speed is not relevant.
momentum change = mass*change in velocity
= 1205*12.5*3.25 kg m/s
The CHANGE in speed is acceleration times time
12.5 * 3.25
That is all you need
The initial speed is not relevant.
momentum change = mass*change in velocity
= 1205*12.5*3.25 kg m/s
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