Question

The 1205 kg physics dragster is traveing ay 35km(easy) when it hits the gas and accelerates at 12.5 m/s^2 for 3.25s. What is change in momentum during this time?

Answer 1

is the initial speed 35km/hr? change that to m/s

momentumchange=mass*(vf-vi)

vf=vi+at=12.5*3.25m/s+vi

vf-vi=12.5*3.25 m/s

Answer 2

BOB what i fail to understand is isnt Vf-vi=(12.5*3.25)-(9.722).

Answer 3

No
The CHANGE in speed is acceleration times time
12.5 * 3.25

That is all you need
The initial speed is not relevant.

momentum change = mass*change in velocity
= 1205*12.5*3.25 kg m/s