Asked by javane
A 873-kg (1930-lb) dragster, starting from rest completes a 403.7-m (0.2523-mile) run in 4.920 s. If the car had a constant acceleration, what would be its acceleration and final velocity?
Answers
Answered by
Writeacher
http://www.jiskha.com/display.cgi?id=1290754007
Answered by
Henry
V = d / t = 403.7 / 492 = 82.1 m/s.
a = (Vf - Vo) / t,
a = (82.1 - 0) / 4.92 = 16,7 m/s^2.
a = (Vf - Vo) / t,
a = (82.1 - 0) / 4.92 = 16,7 m/s^2.
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