triangle PQR has vertices p(-3,5),q(7,3) and r(-1,-5) find the distance between PQ,QR and RP

Answer 1

simply use the "length of line between 2 points" formula.
I will do PQ, you do the other two

PQ = √( (7+3)^2 + (3-5)^2 )
= √(100 + 4)
= √104 = √4 √26
= 2√26