Asked by salim
The initial velocity of a projectile is 12i+13j in m\s.
What is the displacement of a projectile at 0.25 seconds later?
What is the displacement of a projectile at 0.25 seconds later?
Answers
Answered by
Damon
do horizontal and vertical separately
I assume j is up
v = 13 - 9.81 t
y = 0 + 13 t -4.9 t^2
If y is negative, it dug a hole :)
and
x = 12 t
so
d = 12 t i + (13t-4.9t^2) j
I assume j is up
v = 13 - 9.81 t
y = 0 + 13 t -4.9 t^2
If y is negative, it dug a hole :)
and
x = 12 t
so
d = 12 t i + (13t-4.9t^2) j
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