Asked by Fatima
5x+3y=9x-7y
I am having trouble in solving. My answer is ending in fractions. And do far I have gotten y=-1/7
I am having trouble in solving. My answer is ending in fractions. And do far I have gotten y=-1/7
Answers
Answered by
Reiny
5x+3y=9x-7y
10y = 4x
y = 2x/5
Not sure what you mean by "solve".
Since you have 2 unknowns but only one equation, there is no unique solution.
by letting x equal multiples of 5, you will get whole integer solutions for both x and y.
e.g.
x = 5, y = 2
x = 10, y = 4
x = 15, y = 6
x = 0 , y = 0
x = -5, y = -2
etc
if you let x be a non-multiple of 5, you will indeed get fractions.
e.g.
x = 3, y = 6/5
etc
10y = 4x
y = 2x/5
Not sure what you mean by "solve".
Since you have 2 unknowns but only one equation, there is no unique solution.
by letting x equal multiples of 5, you will get whole integer solutions for both x and y.
e.g.
x = 5, y = 2
x = 10, y = 4
x = 15, y = 6
x = 0 , y = 0
x = -5, y = -2
etc
if you let x be a non-multiple of 5, you will indeed get fractions.
e.g.
x = 3, y = 6/5
etc
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