Question

A 400g soccer ball is moving through the air at 3.57m/s [64.8°W of N] horizontally at the top of its flight.

If at that instant, the soccer ball is struck by a 450g crocket ball moving at 5.46m/s [N], and the soccer ball flies off at 4.28m/s[22.4°W of N]. What will be the velocity of the crocket ball immediately after the collision?
| what is the final impulse of the crocket ball in the northward direction?
|| what is the final impulse of the soccer ball in the westward direction?

Answer 1

64.8o W of N = 154.8o CCW.
22.4o W of N. = 112.4o CCW.

M1*V1 + M2*V2 = = M1*V3 + M2*V4.
0.4*3.57m/s[154.8o] + 0.45*5.46m/s[90o]
= 0.4*4.28m/s[112.4o] + 0.45*V4.
1.43m/s[154.8] + 2.46m/s[90o] = 1.71m/s[112.4] + 045V4,
-1.29+0.609i + 2.46i = -0.652+1.58i + 0.45V4,
-1.29 + 3.07i = -0.652 + 1.58i + 0.45V4,
-0.638 + 1.49i = 0.45V4,
V4 = -1.42 + 3.31i = 3.60m/s[-66.8o] = 3.60m/s[66.8o N of W].
= Velocity of crocket ball.