Asked by Brian
Find the magnitude and direction angle θ of the vector.
u=4(cos102°i+sin102°j)
u=4(cos102°i+sin102°j)
Answers
Answered by
Reiny
u=4(cos102°i+sin102°j)
= 4[cos102° , sin102°]
the direction angle is clearly 102°
magnitude = √(16(cos^2 102 + sin^2 102)
= √(16(1))
= 4
= 4[cos102° , sin102°]
the direction angle is clearly 102°
magnitude = √(16(cos^2 102 + sin^2 102)
= √(16(1))
= 4
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