Question
Find the magnitude and direction of a)the resultant b)the equilibrant of two forces 10N acting in the direction N030'E and 15N acting in the eastern direction if boths forces act at a point.
Answers
The equilibrant is equal and in opposite direction to the resulatant.
equilibrant= - resultant
equilibrant= - resultant
All angles are measured CCW from +x-axis.
a. Fr = 10[60o] + 15[0o].
Fr = (10*Cos60+15*Cos0) + (10*sin60+15*sin0)i.
Fr = (5+15) + (8.66+0)i = 20 + 8.66i = 21.8N.[23.4o].
b. Fe = -21.8[23.4o] = 21.8[23.4+180] = 21.8N.[203.4o]
a. Fr = 10[60o] + 15[0o].
Fr = (10*Cos60+15*Cos0) + (10*sin60+15*sin0)i.
Fr = (5+15) + (8.66+0)i = 20 + 8.66i = 21.8N.[23.4o].
b. Fe = -21.8[23.4o] = 21.8[23.4+180] = 21.8N.[203.4o]
please how did you get 23.4?
I need simple explanation
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