Asked by Anneliese
y=x^2 -4x -32. Use this function and identify the axis of symmetry and the vertex.
Thank you.
Thank you.
Answers
Answered by
MathMate
By completing the square,
y=x^2-4x-32
=(x-2)²-4-32
=(x-2)²-36
The line x-2=0 passes through the vertex, hence the vertex is
(2,y(2))=(2, -36)
The line of symmetry of a parabola that opens up or down is the vertical line through the vertex.
y=x^2-4x-32
=(x-2)²-4-32
=(x-2)²-36
The line x-2=0 passes through the vertex, hence the vertex is
(2,y(2))=(2, -36)
The line of symmetry of a parabola that opens up or down is the vertical line through the vertex.
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