Asked by Anneliese
y=x^2 -4x -32. Use this function and identify the axis of symmetry and the vertex.
Thank you.
Thank you.
Answers
Answered by
MathMate
By completing the square,
y=x^2-4x-32
=(x-2)²-4-32
=(x-2)²-36
The line x-2=0 passes through the vertex, hence the vertex is
(2,y(2))=(2, -36)
The line of symmetry of a parabola that opens up or down is the vertical line through the vertex.
y=x^2-4x-32
=(x-2)²-4-32
=(x-2)²-36
The line x-2=0 passes through the vertex, hence the vertex is
(2,y(2))=(2, -36)
The line of symmetry of a parabola that opens up or down is the vertical line through the vertex.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.