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Asked by Anneliese

Y=X^2 -4x -32. Use this function and identify the minimum.

Thank you very much.
8 years ago

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Answered by MathMate
The minimum of a parabola is the y-value of the vertex. See previous response.
8 years ago
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Y=X^2 -4x -32. Use this function and identify the minimum.

Thank you very much.

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