Question

We examine the following reaction at 250C: PCl5(g) ⇌ PCl3(g) + Cl2(g). At equilibrium we find [PCl5] = 3.4 x 10-5 M, [PCl3] = 1.3 x 10-2 M, and [Cl2] = 1.0 x 10-4 M. Calculate the equilibrium constant, Kc.reaction.
(a) 26 (b) 5.1 (c) 2.8 x 10-4 (d) 0.038

Answer 1

Indicate your <I>specific</I> subject in the "School Subject" box, so those with expertise in the area will respond to the question.

I cannot make sense of your question. Maybe someone with physics/chemistry background could.

Online, “*” is used to indicate multiplication to avoid confusion with “x” as an unknown.

Online "^" is used to indicate an exponent, e.g., x^2 = x squared.

(c) 2.8*10^4

Answer 2

The answer is 0.038. Substituting into the equilibrium expression, you have K = (0.013*0.0001)/(0.000034)