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Assuming p>0, what is the positive root of x^2 - 2px - 8p^2 = 0, in terms of p?
1 answer
x = [2p+/-sqrt(4p^2+32p^2) ]2
= [2 p + sqrt(36 p^2) ]/2
= [2 p + 6 p ]/2
= 4 p