Asked by Alec
Assume that x,y and a are positive numbers. Use the properties of logarithms to write the following expression - log a x^6 y^7
a. 42log a x+y
b. 42log a x+7log a y
c. 6log a x+42log a y
d. 6log a x+7log a y
e. 6log a x+6log a y
a. 42log a x+y
b. 42log a x+7log a y
c. 6log a x+42log a y
d. 6log a x+7log a y
e. 6log a x+6log a y
Answers
Answered by
Reiny
assuming that "a" is the base
- log a x^6 y^7
= -(log<sub>a</sub> x^6 + log<sub>a</sub> y^7)
= -(6log<sub>a</sub> x + 7log<sub>a</sub> y)
= -6log<sub>a</sub> x - 7log<sub>a</sub> y
none of your choices are correct, unless there is a typo with that minus sign
- log a x^6 y^7
= -(log<sub>a</sub> x^6 + log<sub>a</sub> y^7)
= -(6log<sub>a</sub> x + 7log<sub>a</sub> y)
= -6log<sub>a</sub> x - 7log<sub>a</sub> y
none of your choices are correct, unless there is a typo with that minus sign
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