In a quarter-mile drag race, two cars start simultaneously from rest, and each accelerates at a constant rate until it either reaches its maximum speed or crosses the finish line. Car A has an acceleration of 11.0 m/s2 and a maximum speed of 110 m/s. Car B has an acceleration of 11.8 m/s2 and a maximum speed of 91.8 m/s. (a) Which car wins the race? (b) By how many seconds does this car win the race?

asked by Thomas

8 years ago

1,493 views

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1

1 answer

Car A: 0.5a*Ta^2 = 400 m.
0.5*11*t^2 = 400. Ta = ?.

Car B: 0.5*11.8*Tb^2 = 400. Tb = ?.

b. T = Ta-Tb.

answered by Henry

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3

Question

In a quarter-mile drag race, two cars start simultaneously from rest, and each accelerates at a constant rate until it either reaches its maximum speed or crosses the finish line. Car A has an acceleration of 11.0 m/s2 and a maximum speed of 110 m/s. Car B has an acceleration of 11.8 m/s2 and a maximum speed of 91.8 m/s. (a) Which car wins the race? (b) By how many seconds does this car win the race?

1 answer

Car A: 0.5a*Ta^2 = 400 m.
0.5*11*t^2 = 400. Ta = ?.

Car B: 0.5*11.8*Tb^2 = 400. Tb = ?.

b. T = Ta-Tb.

Henry · Answer

Car A: 0.5a*Ta^2 = 400 m. 0.5*11*t^2 = 400. Ta = ?. Car B: 0.5*11.8*Tb^2 = 400. Tb = ?. b. T = Ta-Tb.