Asked by Nelson

Draw a block and tackle system of pulleys with a velocity ratio of 5.A block and tackle with a velocity ratio of 5 is used to raise a mass of 25kg through a vertical distanceof 40cm at a steady rate. If the efforts is equal to 60N, determine
a)d distance moved by the effort
b)the work done by the effort in lifting the load
c)the loss in energy involved in lifting the load.
Answered by Anonymous
velocity ratio of 5 implies a distance ratio of 5

5 * 0.40 m = 2 m

work done by arms = 60*2 = 120 Joules

work done by lift on mass = 25*9.81*0.20
= 49.05 Joules

loss in energy = 120 - 49 = 71 Joules
Answered by lekan
how do you get Your question b answer
Answered by Akankwasa Gloria
It has been so helpful to me.
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