Asked by Ummi
A block and tackle system of 5 pulleys is used to raise a mass of 25kg through a vertical distance of 40cm at a steady rate. If the effort is 60N, determine:
1.the distance moved by the effort;
2.the work done by the effort
3.the energy difference between the input and the output energies.
1.the distance moved by the effort;
2.the work done by the effort
3.the energy difference between the input and the output energies.
Answers
Answered by
R_scott
1. .4 m * 5 = 2 m
2. 2 m * 60 N = 120 J
3. 120 J - (25 kg * 9.8 m/s^2 * .4 m) = ? J
2. 2 m * 60 N = 120 J
3. 120 J - (25 kg * 9.8 m/s^2 * .4 m) = ? J
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