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the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times 5 the largerAsked by Omara
The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the large.
Answers
Answered by
Steve
x+y <= 9x-5y
6y <= 8x
3y <= 4x
You might also want to consider
x+y <= |9x-5y|
6y <= 8x
3y <= 4x
You might also want to consider
x+y <= |9x-5y|
Answered by
Reiny
but the integers are consecutive, so
smaller number --- x
next integer ---- x+1
x + x+1 ≤ 9x - 5(x+1)
2x + 1 ≤ 4x - 5
2x ≥ -6
x ≥ -3
Also consider Steve's other possibility .
smaller number --- x
next integer ---- x+1
x + x+1 ≤ 9x - 5(x+1)
2x + 1 ≤ 4x - 5
2x ≥ -6
x ≥ -3
Also consider Steve's other possibility .
Answered by
Steve
It usually helps to read the problem carefully.
Nice work, Reiny
Nice work, Reiny
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