Question
find the 7th term of the geometric progression if the first and 5th terms are 16 and 9 respectively.
Answers
Reiny
a = 16
ar^4 = 9
sub in a = 16
16r^4 = 9
4r = ± 3
r = ± 3/4
7th term = ar^6
= 16(±3/4) = 16(729/4096)
= 729/256
ar^4 = 9
sub in a = 16
16r^4 = 9
4r = ± 3
r = ± 3/4
7th term = ar^6
= 16(±3/4) = 16(729/4096)
= 729/256
Allen
I don't understand
ISAAC
I dont understand