Asked by Anonymous
Find the nth term of the geometric sequence whose initial term is 7 and common ration is 7. (your answer must be a function of n)
Answers
Answered by
Reiny
For a GS,
term<sub>n</sub> = a(r)^(n-1)
so term<sub>n</sub> = 7(7)^(n-1)
= 7^n
term<sub>n</sub> = a(r)^(n-1)
so term<sub>n</sub> = 7(7)^(n-1)
= 7^n
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