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When tuning a piano, a musical play a note that should be at 110 Hz while at the same tapping 110 Hz tuning fork and holding it...Asked by Anonymous
when tuning a piano, amusician plays a note that should be at 110Hz while at the same time tapping a 110Hz tuning fork and holding it next to the strings. He hears beats at 4Hz.
(A) state and explain what frequencies the piano could be producing
(b) explain how the musician now finishes tuning his piano
(C) Draw a sketch graph to show the resultant sound as a variation in displacement against time. Label the time axis with values.
(A) state and explain what frequencies the piano could be producing
(b) explain how the musician now finishes tuning his piano
(C) Draw a sketch graph to show the resultant sound as a variation in displacement against time. Label the time axis with values.
Answers
Answered by
Henry
a. F1 = 110-4 = 106 Hz. = The difference freq.
F2 = 110+4 = 114 Hz = The sum freq.
b. Adjust strings until the notes cannot be heard.
F2 = 110+4 = 114 Hz = The sum freq.
b. Adjust strings until the notes cannot be heard.
Answered by
Bami Haile
What about question c ?
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