Question
A tuning fork with a frequency of 440 Hz is held above a resonance tube that is partially filled with water. Assuming that the speed of sound in air is 342 m/s, for what three smallest heights of the air column will resonance occur? Where will the nodes and anti-nodes occur? (Hint: For resonance to occur, the frequency of the tuning fork must match that of the tube.)
I understand finding the wavelength and finding the height that resonance will occur in the air column but I can't figure out how to find where the nodes and anti nodes occur. Can somebody explain please.
I understand finding the wavelength and finding the height that resonance will occur in the air column but I can't figure out how to find where the nodes and anti nodes occur. Can somebody explain please.
Answers
bobpursley
Look at the figures with the closed tube.
http://media.paisley.ac.uk/~davison/labpage/tube/tube.html
http://media.paisley.ac.uk/~davison/labpage/tube/tube.html
Related Questions
With a tuning fork of 384 hz, resonance tube lengths are acheived at 0.647m and 1.09 m. What is the...
An air column in a glass tube is open at one end and closed at the other by a movable piston. The ai...
When a tuning fork is held over the open end of a very thin tube, as in the figure below, the smalle...
A 71.4cm long tube has a 71.4cm long insert that can be pulled in and out. A vibrating tuning fork i...