Question
A pendulum of Length L cm has time period T seconds. T is directly proportional to the square root of L.
The length of the pendulum is increased by 40%.
What is the percentage increase in the time period?
????????
Multiplier for increasing L = 1.4
Multiplier for increasing T = ?
Thank you.
The length of the pendulum is increased by 40%.
What is the percentage increase in the time period?
????????
Multiplier for increasing L = 1.4
Multiplier for increasing T = ?
Thank you.
Answers
Steve
T = k√L
using L'=1.4L instead, we have
T' =k√L' = k√(1.4L) = k√L √1.4 = T√1.4
using L'=1.4L instead, we have
T' =k√L' = k√(1.4L) = k√L √1.4 = T√1.4
Anonymous
18.3