Question

A pendulum of Length L cm has time period T seconds. T is directly proportional to the square root of L.

The length of the pendulum is increased by 40%.

What is the percentage increase in the time period?

????????

Multiplier for increasing L = 1.4
Multiplier for increasing T = ?

Thank you.

Answer 1

T = k√L
using L'=1.4L instead, we have

T' =k√L' = k√(1.4L) = k√L √1.4 = T√1.4

Answer 2

18.3