Asked by Anonymous
If the pendulum’s length is 2.00 m and ag =9.80 m/s , how many complete oscillations does the pendulum make in 5.00 min?
the answer is 106 but how do i find it !!
the answer is 106 but how do i find it !!
Answers
Answered by
henry2,
P = 2pi*sqrt(L/g) = 2.837 s.
5min. * 60s/min. = 300 s.
300s * 1osc./2.837s = 106 oscillations.
5min. * 60s/min. = 300 s.
300s * 1osc./2.837s = 106 oscillations.
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