Asked by favour

If a man travels 7km N 40degree W and 10km East, find the resultant displacement.
Answered by Steve
7@N40W = <-4.50,5.36>
10@E = <10.00,0.00>

now just add them up and use the normal distance formula.
Answered by David
7*sin40+10*sin90=14.5
7*cos40+10*cos90=5.4
(x^2+y^2)=15.5
Answered by physics
if a man travels 7.0km 30° East of North and then 10km East find the resultant displacement
Answered by physics
if he travels 7.0km west of North 100km East find the resultant displacement
Answered by physics
I want to see the answers of this question
Answered by NURA
If a man travel 7.0km 30 east of north then 10_0km east find the resultant displacement
Answered by Ayomide
R^2=10^2+7^2-2x10x7cos130 degree
R^2=149+89.9
R=15.46km

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Answered by Adebayo abeeb
How does it get cos130
Answered by Evan
What about the sine rule
Answered by Amina
Firstly you would use pythogoras theorem.thats all I know but the problem in solving this is the N40°W😅. Anyway the answer is 8km or N44°W.
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