If a man travels 7km N 40degree W and 10km East, find the resultant displacement.

10 answers

7@N40W = <-4.50,5.36>
10@E = <10.00,0.00>

now just add them up and use the normal distance formula.
7*sin40+10*sin90=14.5
7*cos40+10*cos90=5.4
(x^2+y^2)=15.5
if a man travels 7.0km 30° East of North and then 10km East find the resultant displacement
if he travels 7.0km west of North 100km East find the resultant displacement
I want to see the answers of this question
If a man travel 7.0km 30 east of north then 10_0km east find the resultant displacement
R^2=10^2+7^2-2x10x7cos130 degree
R^2=149+89.9
R=15.46km

Call me on 08125436870 or add me on what app for better clarification
How does it get cos130
What about the sine rule
Firstly you would use pythogoras theorem.thats all I know but the problem in solving this is the N40°W😅. Anyway the answer is 8km or N44°W.