Asked by Zeugen reezy
A given volume of ozone diffused from a certain apparatus in 96seconds calculate the time taken by an equal volume of carbonoxide to diffuse under the same condition?
Answers
Answered by
bobpursley
R1/R2=sqrt(MW2/MW1)
But we are given the inverses of rates, (times), so
T2/T1=sqrt(MW2/MW1)
ozone MW1=16*3=48
CO MW2=28
T1=96seconds
T2 (CO)=96*sqrt(28/48) seconds
But we are given the inverses of rates, (times), so
T2/T1=sqrt(MW2/MW1)
ozone MW1=16*3=48
CO MW2=28
T1=96seconds
T2 (CO)=96*sqrt(28/48) seconds
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