Asked by Key
Solve for x
ax^2 - 2ax - 4 =0
ax^2 - 2ax - 4 =0
Answers
Answered by
Steve
just use the quadratic formula:
x = (2a±√(4a^2+16a))/(2a)
= (2a±2√(a^2+4a))/(2a)
= 1±√(a^2+4a)/a
or
= 1±√(1 + 4/a)
x = (2a±√(4a^2+16a))/(2a)
= (2a±2√(a^2+4a))/(2a)
= 1±√(a^2+4a)/a
or
= 1±√(1 + 4/a)
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