Question

1. Solve the equation below for x interms of a

4(ax+3)-3ax=25+3a





2. The formula for the sum of the degree measures of the interior angles of a polygon is S=180(n-2). Solve for n, the number of sides of the polygon, in terms of S.




IM STRUGGLING PLEASE HELP

Answer 1

these just use the normal sequences of operations...

4(ax+3)-3ax=25+3a
4ax+12-3ax = 25+3a
ax+12 = 25+3a
ax-3a = 25-12
a(x-3) = 12
a = 13/(x-3)

S=180(n-2)
S = 180n-360
S+360 = 180n
n = (S+360)/180 = S/180 + 2

Answer 2

1.

4 ( ax + 3 )-3 ax = 25 + 3a

4 * ax + 4 * 3 - 3 ax = 25 + 3a

4 ax + 12 - 3 ax = 25 + 3a

4 ax - 3 ax + 12 = 25 + 3a

ax + 12 = 25 + 3a Subtract 12 to both sides

ax + 12 - 12 = 25 + 3a - 12

ax = 25 - 12 + 3a

ax = 13 + 3a Subtract 3a to both sides

ax - 3a = 13 + 3a - 3a

ax - 3a = 13

a ( x - 3 ) = 13 Divide both sides by a

x - 3 = 13 / a Add 3 to both sides

x - 3 + 3 = 13 / a + 3

x = 13 / a + 3 = 13 / a + 3a / a

x = ( 13 + 3a ) / a


2.

S = 180 ( n - 2 ) Divide both sides by 180

S / 180 = n - 2 Add 2 to both sides

S / 180 + 2 = n - 2 + 2

S / 180 + 2 = n

n = S / 180 + 2

Answer 3

Where you got the s from ?

Answer 4

bosianian it said solve in terms of S

Answer 5

I solved it like:
S=180(n-2) Distribute 180
S=180n-360 Add 360
S+360=180n Divide by 180
S+2=n
I’m confused as to what I am doing wrong.